((8x^8y^2)/(x^-2y^-3))^-1

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Solution for ((8x^8y^2)/(x^-2y^-3))^-1 equation: 


D( x )

(8*x^8*y^2)/(x^-2*y^-3) = 0

x = 0

x^-2*y^-3 = 0

(8*x^8*y^2)/(x^-2*y^-3) = 0

(8*x^8*y^2)/(x^-2*y^-3) = 0

8*x^10*y^5 = 0 // : 8*y^5

x^10 = 0

x = 0

x = 0

x = 0

x^-2*y^-3 = 0

x^-2*y^-3 = 0

x^-2*y^-3 = 0 // : y^-3

x^-2 = 0

x należy do O

x in (-oo:0) U (0:+oo)

((8*x^8*y^2)/(x^-2*y^-3))^-1 = 0

1/8*x^-10*y^-5 = 0 // : 1/8*y^-5

x^-10 = 0

x należy do O

x belongs to the empty set

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